Respuesta :

geerky42
You just replace t to -3t

So h(-3t) would be -2(-3t)+2 = 6t+2

If you just meant h(-3) then that would be 6+2 = 8 via same steps.
What you want to do is plug in -3t for the value of t which will give you
[tex]h( - 3t) = - 2( - 3t) + 2 [/tex]
After doing all the necessary operations, you will end up with
[tex]6t + 2[/tex]
which is your answer

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