How many chloride ions are present in 1.00 moles of CaCl2

1 mole of CaCl2 consists of 1 mole Ca2+ and 2 mole Cl–. If 1 mole of Cl– is 6.02 x 1023 Cl– ions, then 1 mole of CaCl2 contains (2 x 6.02 x 1023) Cl– ions or 1.20 x 1024 Cl– ions.

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okpalawalter8 okpalawalter8 · Answer 2 · 2021-10-21T14:57:32+02:00

We have that for the Question "How many chloride ions are present in 1.00 moles of 2 CaCl " it can be said that There are [tex]1 mole CaCl_2= 1.204*10^{24} Cl- ions[/tex] in 1.00 moles of CaCl_2

[tex]1 mole CaCl_2= 1.204*10^{24} Cl- ions[/tex]

From the question w e are told

How many chloride ions are present in 1.00 moles of 2 CaCl

Generally the equation for the is mathematically given as

CaCl_2=Ca^{+2}+2Cl-

Therefore

1 mole of CaCl_2 has 1 mole Ca2+ and has 2 mole Cl–

Where

1 mole of Cl– = 6.02 * 10^{23}

Therefore

[tex]1 mole\ CaCl_2= 2*6.02 * 10^{23}[/tex]

[tex]1 mole CaCl_2= 1.204*10^{24} Cl- ions[/tex]

Therefore

There are [tex]1 mole CaCl_2= 1.204*10^{24} Cl- ions[/tex] in 1.00 moles of CaCl2

[tex]1 mole CaCl_2= 1.204*10^{24} Cl- ions[/tex]

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