As we know
tan A = [tex]\frac{1}{Cot A}[/tex]
As given , tan 0 = [tex]\frac{-3}{8}[/tex]
So, Cot A is inverse of Tan A.
So, the value of Cot 0 = [tex]\frac{1}{Tan 0}=\frac{1}{\frac{-3}{8}}[/tex]
Option (a) [tex]\frac{1}{\frac{-3}{8}}[/tex] is true.
The value of Cot0 is -8/3 or 1/(- 3/8) if the value of tan 0 is -(3)/(8) which is the ratio of the side opposite to the angle to the hypotenuse, and the cot is the ratio of the side adjacent to the hypotenuse option (a) is correct.
The trigonometric ratio is defined as the ratio of the pair of a right-angled triangle.
We have:
[tex]\rm Tan0 = -\frac{3}{8}[/tex]
We know that Tan is the ratio of the opposite to the adjacent and Cot is the ratio of the adjacent to the opposite which is the opposite of Tan.
[tex]\rm Cot0 =\frac{1}{Tan0}[/tex]
Put the value of Tan0 in the above expression, we get:
[tex]\rm Cot0 =\frac{1}{-\frac{3}{8} }[/tex]
[tex]\rm Cot0 = -\frac{8}{3}[/tex]
Thus, the value of Cot0 is -8/3 if the value of tan 0 is -(3)/(8) which is the ratio of the side opposite to the angle to the hypotenuse, and the cot is the ratio of the side adjacent to the hypotenuse.
Know more about trigonometry here:
brainly.com/question/26719838
#SPJ3
