Respuesta :
Ok so we know:
The time (t) is 18seconds
The acceleration (a) is 2.2m/s2
The displacement (r) is 660
Using the equation
[tex]r = ut + \frac{1}{2} a {t}^{2} [/tex]
With 'u' being the initial velocity we want, we get:
[tex]660 = 18u + 356.4[/tex]
So:
[tex]18u = 303.6[/tex]
So:
[tex]u = 16.8666[/tex]
So the original/initial velocity was 16.8666 or 16.87 m/s
Hope this helped
The time (t) is 18seconds
The acceleration (a) is 2.2m/s2
The displacement (r) is 660
Using the equation
[tex]r = ut + \frac{1}{2} a {t}^{2} [/tex]
With 'u' being the initial velocity we want, we get:
[tex]660 = 18u + 356.4[/tex]
So:
[tex]18u = 303.6[/tex]
So:
[tex]u = 16.8666[/tex]
So the original/initial velocity was 16.8666 or 16.87 m/s
Hope this helped
The initial velocity of the Jeep is 16.87 m/s
From one of the equations of kinematics for linear motion
We have that
[tex]s = ut + \frac{1}{2}at^{2}[/tex]
Where s is the distance or displacement
u is the initial velocity
a is the acceleration
and t is the time
From the question,
a = 2.2 m/s²
t = 18 secs
s = 660 meters
Putting the above parameters into the formula, we get
[tex]660 = (u \times 18) + \frac{1}{2} \times 2.2 \times 18^{2}[/tex]
[tex]660 = 18u + 1.1 \times 324[/tex]
[tex]660 = 18u + 356.4[/tex]
∴ [tex]18u = 660 -356.4[/tex]
[tex]18u = 303.6[/tex]
Divide both sides by 18
[tex]\frac{18u}{18}=\frac{303.6}{18}[/tex]
∴ u = 16.87 m/s
Hence, the initial velocity of the Jeep is 16.87 m/s
Learn more here: https://brainly.com/question/24612027
