the members of the boosters organization at your high school bought new balls for the school. They spent $24.00 per basketball and $33.00 per football, spending a total of $882.00. They bought 6 more footballs than basketballs. How many of each type of ball did they buy?

Respuesta :


6x$33=$198 (difference of 6 footballs)
$882-$198=$684 
$24+$33=$57 (sum of 1 set)
$684÷$57=12(no. of sets)
12x1=12 (basketballs)
12+6=18 (footballs)

Ans:
12 basketballs 
18 footballs


This question is based on concept of normal calculations. Therefore, total number of basketballs are 12x1=12 and, total number of footballs are 12+6=18 would be buy.

Given:

They spent $24.00 per basketball and $33.00 per football, spending a total of $882.00. They bought 6 more footballs than basketballs.

We need to determined that how many each type of balls did they buy.

According to question:

We have to calculated difference of 6 footballs is,

6 x $33 = $198  

Total amount spending on both the balls is $882.00

$882-$198=$684

Now, calculating spending on 1 set i.e. 1 football and 1 basketball

$24+$33=$57 (sum of 1 set)

Now, calculated total number of sets,

$684÷$57=12(no. of sets)

Therefore, total number of basketballs are 12x1=12 and, total number of footballs are 12+6=18.

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https://brainly.com/question/22947369