Respuesta :
6x$33=$198 (difference of 6 footballs)
$882-$198=$684
$24+$33=$57 (sum of 1 set)
$684÷$57=12(no. of sets)
12x1=12 (basketballs)
12+6=18 (footballs)
Ans:
12 basketballs
18 footballs
This question is based on concept of normal calculations. Therefore, total number of basketballs are 12x1=12 and, total number of footballs are 12+6=18 would be buy.
Given:
They spent $24.00 per basketball and $33.00 per football, spending a total of $882.00. They bought 6 more footballs than basketballs.
We need to determined that how many each type of balls did they buy.
According to question:
We have to calculated difference of 6 footballs is,
6 x $33 = $198
Total amount spending on both the balls is $882.00
$882-$198=$684
Now, calculating spending on 1 set i.e. 1 football and 1 basketball
$24+$33=$57 (sum of 1 set)
Now, calculated total number of sets,
$684÷$57=12(no. of sets)
Therefore, total number of basketballs are 12x1=12 and, total number of footballs are 12+6=18.
For more details, prefer this link:
https://brainly.com/question/22947369