Answer:
option B
Step-by-step explanation:
The given inequality is 4x + 2y < 3
2y < 3 - 4x
or [tex]\frac{2y}{2}<\frac{3-4x}{2}[/tex]
y < (-2x) + [tex]\frac{3}{2}[/tex]
Here slope of the line is ( -2 )
So the line will pass through either ( 0, 1.5 ) and ( x, 0 )
Therefore, from the formula of slope
slope = [tex]\frac{y-y'}{x-x'}[/tex]
( -2) = [tex]\frac{0-1.5}{x}[/tex]
2x = 1.5
x = [tex]\frac{1.5}{2}[/tex]
= 0.75
Therefore, points from which this line passes are ( 0, 1.5 ) and ( 0.75, 0 )
Now from the inequality " < " sign denotes that shaded portion will be below on left side of the line.
Therefore, option B will be the answer.
