Answer:
The product of [tex](y+3)(y^{2}-3y+9)[/tex] is [tex]y^{3}+27 [/tex]
Step-by-step explanation:
we need to find the product of binomial by the trinomial of the expression:
[tex](y+3)(y^{2}-3y+9)[/tex]
Multiply term wise,
⇒[tex]y\times y^{2}-y\times 3y+y\times 9+ 3\times y^{2} -3\times 3y +3\times 9 [/tex]
⇒[tex]y^{3}- 3y^{2}+9y+ 3y^{2} -9y +27 [/tex]
combine the line terms together,
⇒[tex]y^{3}- 3y^{2}+ 3y^{2} +9y-9y +27 [/tex]
⇒[tex]y^{3}+27 [/tex]
Hence, the product of [tex](y+3)(y^{2}-3y+9)[/tex] is [tex]y^{3}+27 [/tex]
