Answer:
one solution (0,-1)
Step-by-step explanation:
[tex]y=5x-1[/tex]
[tex]-15x-3y=3[/tex]
LEts solve for x and y, Substitute 5x-1 for y in second equation
[tex]-15x-3y=3[/tex]
[tex]-15x-3(5x-1)=3[/tex]
[tex]-15x-15x+3=3[/tex]
Combine like terms
[tex]-30x+3=3[/tex]
Subtract 3 on both sides
[tex]-30x=0[/tex]
Divide both sides by -30
[tex]x=0[/tex]
Now plug in 0 for x in first equation
[tex]y=5x-1[/tex]
[tex]y=5(0)-1=-1[/tex]
So one solution (0,-1)
