The given balanced equation is:
2Al + 3FeO --> 3Fe +Al2O3
From this balanced equation, we can see that:
2 moles of aluminum are required to react with 3 moles of iron oxide.
Therefore, to know the number of moles of aluminum required to react with 13.2 moles of iron oxide, you just have to do cross multiplication as follows:
2 moles of Al ..................> 3 moles of FeO
?? moles of Al ....................> 13.2 moles of FeO
number of moles of Al = (13.2*2) / (3) = 8.8 moles
