which of the following is the surface area of the right cylinder below
a. 240pi^
b. 540pi^
c. 225pi^
d. 252pi^

The answer is 252 pi units.
Explanation:
The surface area of a right cylinder is [tex]2\pi rh+2\pi r^{2}[/tex]
So, given height is = 15 units
Given radius is = 6 units.
So, putting these values in the formula, we get:
[tex](2\pi *6*15)+(2\pi (6)^{2} )[/tex]
= [tex](2\pi *90)+(2\pi *36)[/tex]
= [tex]180\pi +72\pi =252\pi[/tex] units
Hence, the answer is option D.
The surface area of the right cylinder is [tex]\boxed{252\pi {\text{uni}}{{\text{t}}^2}}.[/tex]
Further explanation:
The formula for the surface area of the cylinder can be expressed as,
[tex]\boxed{{\text{Surface area}} = 2\pi r\left( {r + h} \right)}[/tex]
Here, “r” represents the radius of the cylinder and “h” represents the height of the cylinder.
Given:
The radius of the cylinder is {\text{6 units}} and the height of the cylinder is [tex]{\text{15 units}}.[/tex]
The options are as follows,
(A). [tex]240\pi {\text{ unit}}{{\text{s}}^2}[/tex]
(B). [tex]540\pi {\text{ unit}}{{\text{s}}^2}[/tex]
(C). [tex]225\pi {\text{ unit}}{{\text{s}}^2}[/tex]
Explanation:
The surface area of the right cylinder can be obtained as follows,
[tex]\begin{aligned}{\text{Surface area}} &= 2\pi r\left( {r + h} \right)\\&= 2\pi\times \left( 6 \right) \times \left( {6 + 15} \right)\\&= 12\pi \times 21\\&= 252\pi\\\end{aligned}[/tex]
The surface area of the right cylinder is [tex]\boxed{252\pi {\text{uni}}{{\text{t}}^2}}.[/tex]
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Answer details:
Grade: High School
Subject: Mathematics
Chapter: Mensuration
Keywords: Cylinder, surface area of the cylinder, curved surface area, volume, right cylinder, height of the cylinder, and radius of the cylinder.