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Calculate the time needed to accelerate a 40 kg object from 2 m/s to 12 m/s if a force of 8 N is applied. a 400 seconds b 10 seconds c 50 seconds d 0.2 seconds

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samuraijack
The answer is C. 50 s

Given: M = 40 Kg;  Vi = 2 m/s;  Vf = 12 m/s;  F = 8 N

Formula:  F = ma  but a = Vf - Vi/t  substitute acceleration "a" from F = ma

F = m(Vf - Vi)/t   Solve for time "t"   t = m(Vf - Vi)/F

t = 40 Kg (12 m/s - 2 m/s)/8 Kg.m/s²  

t = 50 s

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