Let O be the intersection of the vertical line through ZX, and the horizontal line through YW.
The coordinates of this point are clearly (5, 2) as it is at the same x-coordinate as X and Z, and y-coordinate as Y and W.
So, YZO is a right triangle. By the Pythagorean theorem:
[tex]ZY= \sqrt{{YO}^2+{OZ}^2}= \sqrt{2^2+3^2}= \sqrt{4+9}= \sqrt{13} [/tex].
Since all sides of a rhombus are equal, then the perimeter is :
[tex]P(XWZY)=4 \sqrt{13} [/tex] units.
Answer: third choice.
