X is the easy one to solve here. A triangle must have 180 degrees. Add 90 to 38 and subtract that value from 180. This results in x = 52 Degrees. Y is a little bit more difficult. Because The two lines are parallel, Angle CDB is equal to the angle just above y-12. That angle is equal to x, in other words. This angle and y-12 must equal 180 when they are added together, as this is the value for degrees of a line. So, 180= (y-12) + 52. Just solve this algebraically, and is should result in y = 140 degrees.
Tldr: y = 140, x= 52
