acceleration=change in velocity divided by change in time or [tex]a=\frac{\Delta v}{\Delta t}[/tex]
we are given that it goes from 5m/s to 15m/s
[tex]\Delta v=v_f-v_0[/tex]
in this case, [tex]\Delta v=15\frac{m}{s}-5\frac{m}{s}=10\frac{m}{s}[/tex]
and the change in time or [tex]\Delta t[/tex] is 1 second because this change occurs over a period of 1 second
so the acceleration is [tex]a=\frac{10\frac{m}{s}}{1s}=10\frac{m}{s^2}[/tex]
the acceleration is [tex]10\frac{m}{s^2}[/tex]
