Answer:
AD=2,667
Step-by-step explanation:
Given that ABC is a right triangle, right angled at B
BD is the altitude
Since DB and DC are given we can find tan c using right triangle BCD
tan c = [tex]\frac{DB}{DC} =\frac{4}{6}[/tex]
Angle ABD is complement of angle A
In triangle ABC , C is complement of angle A
Hence C = angle ABD
[tex]tan ABD = tan C =\frac{AD}{DB} =\frac{AD}{4}[/tex]
Simplify to get
[tex]AD = 4tanC=4(\frac{4}{6} )\\=\frac{8}{3}[/tex]
