A swimming pool had 2.5 million liters of water in it. Some water evaporated, and then the pool only had 2 million liters of water in it. What percent of the water evaporated?

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belinda1963 belinda1963

06-01-2018
Mathematics

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A swimming pool had 2.5 million liters of water in it. Some water evaporated, and then the pool only had 2 million liters of water in it. What percent of the water evaporated?

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cerverusdante cerverusdante · Answer 1 · 2018-01-18T23:35:49+01:00

First we need to find the liters of water that evaporated; we know that originally we had 2.5 million (2500000) liters of water, and after some of it evaporated we left with tow million liters (2000000), so:
2500000 - 2000000 = 500000 liters evaporated

Now, we can establish a rule of three ans solve for x to obtain the percentage of liters that evaporated:
2500000 -----> 100%
500000 -----> x%
[tex] \frac{2500000}{500000} = \frac{100}{x} [/tex]
[tex]x= \frac{(500000)(100)}{2500000} [/tex]
[tex]x=20[/tex]

We can conclude that 20% is the percentage of water that evaporated.

W0lf93 W0lf93 · Answer 2 · 2018-01-19T23:42:28+01:00

20% of the water evaporated. First, we must obtain the difference. The pool started with 2.5 million liters and ended with 2 million liters. 2.5 million - 2 million = 0.5 million. Next, we must identify what percentage of the water evaporated. We do that by taking the difference (0.5 million) and dividing by the original total (2.5 million). 0.2 million/2.5 million = 0.2 Lastly, we must convert to a percentage. Converting requires that we multiply by 100. 0.2 X 100 = 20%.