A bike first accelerates from 0.0 m/s to 5.0 m/s in 4.5s, then continues at this constant speed for another 4.5 s. What is the total distance traveled by the bike?

Respuesta :

Assuming constant acceleration, the distance travelled in the first 4.5s is:

0.5*5.0*4.5 = 11.25m

The distance travelled in the next 4.5s is:

5.0*4.5 = 22.5m

The total distance travelled is:

11.25 + 22.5 = 33.75m

The total distance traveled by the bike is 33.75 m.

Explanation:

Given that,

Initial speed u= 0.0 m/s

Final speed v= 5.0 m/s

Time [tex]t_{1}= 4.5 s[/tex]

Time for constant speed [tex]t_{2}= 4.5s[/tex]

We need to calculate the total distance traveled by the bike

Using formula for the distance

[tex]d=d_{1}+d_{2}[/tex]

[tex]d=(\dfrac{v+u}{2})\times t_{1}+v\times t_{2}[/tex]

Where,

v = final speed

u = initial speed

[tex]t_{1}[/tex] = time for first accelerates

[tex]t_{2}[/tex] = time for constant speed

Put the value into the formula

[tex]d=(\dfrac{5+0}{2})\times4.5+5.0\times4.5[/tex]

[tex]d=33.75 m[/tex]

Hence, the total distance traveled by the bike is 33.75 m.

Reference :

https://brainly.com/question/3397321