Respuesta :

shinmin
You must set the equations equal to each other.
Meaning, 3y - 5 = 5y
divide both sides by -3y, you'll get -5/2.

Then make an equation:
2ax = bd
2(3y-5) = 5y
6y − 10 = 5y

Subtract 5y from both sides.
y − 10 =0

Add 10 to both sides.

y = 10
calculista

we know that

If the parallelogram ABCD is a rectangle

then

[tex]BD=AC\\AC=AX+XC\\AX=XC[/tex]

so

[tex]2AX=BD[/tex] ------> equation A

Substitute the given values in the equation A

[tex]2(3y-5)=5y[/tex]

Solve for y

[tex]6y-10=5y[/tex]

[tex]6y-5y=10[/tex]

[tex]y=10[/tex]

therefore

the answer is

[tex]y=10[/tex] units

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