Respuesta :
Total distance is calculated by taking summation of Polar express and the rice bridge. So Total distance is 500 m which is 0.5 Km.
Time is 30 sec which when converts to hours= 30/3600= 0.0083 hrs.
So Speed= Distnace/ Time
= 0.5/0.0083
=60.2km/hr
Hence in this case the speed of train is calculated to be 60.2 Km/hr.
Given that the length of the train is 100 m when the train covers the 400 m of the bridge; the length o the train, 100 m, is still on the bridge. The actual distance that the train covers to cross the bridge is 400 m (the length of the bridge) plus 100 m (the length of the train), which is equal to 500 m.
Now, [tex]500m( \frac{1km}{1000m} )= \frac{1}{2} km[/tex], and [tex]30s( \frac{1h}{3600s} )= \frac{1}{120} h[/tex]
We know that [tex]d=vt[/tex], so [tex]v= \frac{d}{t} [/tex].And for our previous calculation we also know that [tex]d= \frac{1}{2} km[/tex] and [tex]t= \frac{1}{120} km[/tex]. The only thing left is replacing those values in our equation:
[tex]v= \frac{ \frac{1}{2}km }{ \frac{1}{120} h} [/tex]
[tex]v= \frac{120km}{2h} [/tex]
[tex]v=60kmh[/tex]
We can conclude that the speed of the train is 60 kmh.
Now, [tex]500m( \frac{1km}{1000m} )= \frac{1}{2} km[/tex], and [tex]30s( \frac{1h}{3600s} )= \frac{1}{120} h[/tex]
We know that [tex]d=vt[/tex], so [tex]v= \frac{d}{t} [/tex].And for our previous calculation we also know that [tex]d= \frac{1}{2} km[/tex] and [tex]t= \frac{1}{120} km[/tex]. The only thing left is replacing those values in our equation:
[tex]v= \frac{ \frac{1}{2}km }{ \frac{1}{120} h} [/tex]
[tex]v= \frac{120km}{2h} [/tex]
[tex]v=60kmh[/tex]
We can conclude that the speed of the train is 60 kmh.