1. Set f(k) = 25
k2 + 2k + 1 = 25
k2 + 2k - 24 = 0
(k - 4)(k + 6) = 0
So two limiting values in the domain are -4 and 6
2. Set f(k) = 64
k2 + 2k + 1 = 64
k2 + 2k - 63 = 0
(k - 7)(k + 9) = 0
So the other two limits are -9 and 7
The domain is [-9, -4] ∪ [6, 7]
Mark as Brainliest Answer Please! TH.
