Respuesta :
The equation of a (horizontal) plane through (3,2,4) is a plane that has a value of z=4 everywhere on the plane.
Therefore the equation of the required plane is z=4.
Therefore the equation of the required plane is z=4.
A plane may be defined either by 3 space points or by a room point, and the direction perpendicular to the plane can be ascertained by a regularisation vector, and the further calculation can be defined as follows:
Suppose that n is the regular horizontal plane vector < 0, 0, 1>.
The point's coordination (3,2,4)
The general equation for an aircraft is:
[tex]n \cdot <x-x_0, y-y_0,z-z_0> =0\\\\\to <(0,0,1)> \cdot <x-x_0, y-y_0,z-z_0> =0\\\\\to <(0,0,1)> \cdot <x-(4), y-(2),z-(4)> =0\\\\\to 0(x-3)+ 0(y-2)+ 1(z-4)> =0\\\\\to z=4\\\\[/tex]
The equation from point to point of a horizontal plane (3,2,4) is, therefore, z= 4
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brainly.com/question/11170530
