The question asks us to find the value of [tex]\theta[/tex] such that [tex]tan(\theta)=sin(\theta)[/tex]. First, we subtract [tex]sin(\theta)[/tex] from both sides, which gives us [tex]tan(\theta)-sin(\theta)=0[/tex]. Now, we need to express the equation as [tex]sin[/tex] and [tex]cos[/tex]. When we do this, we get [tex] \frac{sin(\theta)}{cos(\theta)} -sin(\theta)=0[/tex]. After simplifying, we get [tex] \frac{sin(\theta)-sin(\theta)cos(\theta)}{cos(\theta)} =0[/tex]. All that's left now is factoring and simplifying, giving us [tex]\boxed{\theta=2\pi}[/tex] as an answer. Hope this helped and have a phenomenal day!
