If v = 15 km/h We have:
d1 = 30 km
d2 = 17 km
Since speed = distance/time follows time = distance/speed.
The total time of the entire trip is is the sum of the time of the first 30 km and the time of the remaining 17 km:
d1/v + d2/(v + 2) = 30/15 + 17/(15 + 2) = 2 + 1 = 3 hours
The answer is t=3hours
The question is incomplete. This is the complete question:
For the first 30 km, the bicyclist rode with a speed of v km/hour. For the remaining 17 km he rode with a speed which was 2 km/hour greater than his original speed. How much time did the bicyclist spend on the entire trip? Let t be the time (in hours), and find t if: v = 15
Answer:
The total time the bicyclist spent on the entire trip = T1 + T2 = 2 hours + 1 hour = 3 hours
Step-by-step explanation:
For the first 30 km, the bicyclist rode with an original speed = 15 km/hour
For the remaining 17 km, the bicyclist rode with a speed = 15 + 2 = 17 km/hour
Generally, speed = distance ÷ time
Therefore, time = distance ÷ speed
The time spent on travelling the first distance of 30 km = T1 = 30 ÷ 15 = 2 hours
and the time spent on travelling the second distance of 17 km = 17 ÷ 17 = 1 hour
Therefore, the total time the bicyclist spent on the entire trip = T1 + T2 = 2 hours + 1 hour = 3 hours.
