A 565 N rightward force pulls a large box across the floor with a constant velocity of 0.75 m/s. If the coefficient of friction is 0.8, what is the weight of the box?
The first thing you should know is that the friction force is equal to the coefficient of friction due to normal force. Therefore, clearing the normal force we have: The friction is 565N. (565 / 0.8) = 706.25N. weight.
