You play a game that involves spinning the money wheel shown. you spin the wheel twice find the probability that you get more than $500 on your first spin and then go bankrupt on your second spin. round your answer to the nearest tenth

Answer:
Probability that you get more than $500 on your first spin and then go bankrupt on your second spin is:
0.02
Step-by-step explanation:
There are 24 segments on the wheel in total.
6 segment are of more than $500 and 2 are the bankruptcy spaces.
P(more than $500 on first spin and bankrupt on second spin)
=P(more than $500 on first spin)×P(bankrupt on second)
=
[tex]\dfrac{6}{24}\times \dfrac{2}{24}\\ \\=\dfrac{1}{4}\times \dfrac{1}{12}\\ \\=\dfrac{1}{48} \\\\=0.02[/tex]
Hence, probability that you get more than $500 on your first spin and then go bankrupt on your second spin is:
0.02
Probability tells the chances of an event occurring. The probability that we get more than $500 on our first spin and then go bankrupt on your second spin is 2.778%.
The probability helps us to know the chances of an event occurring.[tex]\rm{Probability=\dfrac{Desired\ Outcomes}{Total\ Number\ of\ outcomes\ possible}[/tex]
Given to us
Number of division that point (prize > $500) = 8
Number of division that point bankrupt = 2
Total number of divisions of the wheel = 24
To calculate the probability of that we get more than $500 on our first spin and then go bankrupt on your second spin.
[tex]\rm{Probability(Prize>\$500)=\dfrac{8}{24} = \dfrac{1}{3}[/tex]
[tex]\rm{Probability(Bankrupt)=\dfrac{2}{24} = \dfrac{1}{12}[/tex]
Therefore,
[tex]\rm Probability = Probability(Prize>\$500) \times Probability(Bankrupt)[/tex]
[tex]\rm Probability =\dfrac{1}{3} \times \dfrac{1}{12} = \dfrac{1}{36} = 0.02778 = 2.778\%[/tex]
Hence, the probability that we get more than $500 on our first spin and then go bankrupt on your second spin is 2.778%.
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