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Dejanras
Answer is: 1,6·10²².
Molecular formula of ibuprofen is C₁₃H₁₈O₂.
m(C₁₃H₁₈O₂) = 0,425 g.
n (C₁₃H₁₈O₂) = m(C₁₃H₁₈O₂) ÷ m(C₁₃H₁₈O₂)
n(C₁₃H₁₈O₂) = 0,425g ÷206,3 g/mol = 0,002mol.
n(C) : n(C₁₃H₁₈O₂) = 13 : 1
n(C) = 0,026 mol.
N(C) = n(C) · Na = 0,026 mol · 6·10²³ 1/mol = 1,6·10²².
Na - Avogadro number.

Explanation:

It is known that the chemical formula of Ibuprofen is [tex]C_{13}H_{18}O_{2}[/tex].

According to Avogadro, 1 mole of an atom contains [tex]6.022 \times 10^{23}[/tex] atoms.

As molar mass of Ibuprofen is 206.29 g/mol. So, number of moles of ibuprofen will be calculated as follows.

            No. of moles = [tex]\frac{mass}{\text{molar mass}}[/tex]

                                  = [tex]\frac{0.425 g}{206.29 g/mol}[/tex]

                                  = [tex]2.06 \times 10^{-3}[/tex] mol

Since. there are 13 atoms of carbon present in a molecule of ibuprofen. Hence, total atoms of carbon present in [tex]2.06 \times 10^{-3}[/tex] mol of Ibuprofen will be as follows.

       [tex]2.06 \times 10^{-3} mol \times 13 \times 6.022 \times 10^{23}[/tex]

         = [tex]0.161 \times 10^{23}[/tex] atoms

Thus, we can conclude that there are [tex]0.161 \times 10^{23}[/tex] atoms of carbon are in 0.425 g of ibuprofen.

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