What is the distance between the points (2, 1) and (14, 6) on a coordinate plane?

The formula for this problem is D = √((y₂ - y₁)² + (x₂ - x₁)²))
So plug in the variables and solve.
D = √((6-1)2 + (14-2)2))D = √( 25 + 144 )D = √169D = 13
I hope this helps love! :)

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RajarshiG RajarshiG · Answer 2 · 2022-05-24T15:17:47+02:00

The distance between two points are (2, 1) and (14, 6) is 13 units.

What is the distance between two points on a coordinate plane?

The distance between two points in a coordinate plane is the smallest distance between them. In coordinate plane this distance can be measured easily using Pythagoras Theorem.

Given two points are (2, 1) and (14, 6).

The distance between two points (x₁, y₁) and (x₂, y₂)on coordinate plane is

= √[(x₂ - x₁)² + (y₂ - y₁)²]

= √[(14 - 2)² + (6 - 1)²] units

= √[144 + 25] units

= √(169) units

= 13 units (as the distance can't be negative)

Learn more about the distance between two points here: https://brainly.com/question/16319826

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