Respuesta :
Answer:
[tex]31.4,32.6[/tex]
Step-by-step explanation:
In the group experiment, 225 readings were taken, the estimated sample average or mean was 32 micro grams per cubic meter and the standard deviation of the sample measurement was 3.
So here,
n = sample size = 255,
μ = mean = 32,
σ = standard deviation = 3.
We have to find the confidence interval of 99.7% around the mean. For confidence interval of 99.7% z score is 3.
We know that confidence interval is,
[tex]=\mu \pm z\dfrac{\sigma}{\sqrt{n}}[/tex]
Putting the values,
[tex]=32 \pm 3\dfrac{3}{\sqrt{225}}[/tex]
[tex]=32 \pm 3\dfrac{3}{15}[/tex]
[tex]=32 \pm \dfrac{9}{15}[/tex]
[tex]=32 \pm 0.6[/tex]
[tex]=31.4,32.6[/tex]