We are asked to find the area of a triangle and the area of a parallelogram. The area of a triangle can be expressed by the formula [tex]A= \frac{1}{2} bh[/tex]. Similarly, the area of a parallelogram can be found using the formula [tex]A=bh[/tex]. In both formulas, [tex]b=base[/tex] and [tex]h=height[/tex].
Area of a Triangle:
Formula: [tex]A= \frac{1}{2} bh[/tex]
[tex]b=6m^3n^4[/tex]
[tex]h=5n[/tex]
Plug them in -
[tex]A= \frac{1}{2}(6m^3n^4)(5n)[/tex]
Multiply -
[tex]\boxed{A=15m^3n^5}[/tex]
Parallelogram:
Formula: [tex]A=bh[/tex]
[tex]b=6a^4b^2[/tex]
[tex]h=3a^3b^2[/tex]
Plug values in -
[tex]A=(6a^4b^2)(3a^3b^2)\Rightarrow \boxed{A=18a^7b^4}[/tex]
Hope this helped!
