the perimeter of a rectangle is 40 feet. the ratio of the width to the length is 2:3. find the length and width

the perimeter of a rectangle is 40 feet the ratio of the width to the length is 23 find the length and width class=

Respuesta :

length(l)= 2x
width(w)= 3x
Perimeter(P) = 2w+2l= 40 ft
1/2P= w+l= 20ft

w+l=20
(3x)+(2x)=20
5x=20
x= 4


length= 2x= 2(4)= 8ft
width= 3x= 3(4)= 12ft

Answer:
length= 8ft
width= 12ft

Length and width of a given rectangle is equals to [tex]12[/tex] feet and [tex]8[/tex] feet respectively.

What is rectangle?

" Rectangle is defined as the quadrilateral whose  opposite side are  congruent  and parallel to each other , each interior angle is of measure [tex]90[/tex] degrees."

Formula used

Perimeter of a rectangle [tex]= 2 ( length + width)[/tex]

According to the question,

Given,

Perimeter of a rectangle [tex]= 40[/tex] feet

Ratio of the width to the length [tex]=\frac{2}{3}[/tex]

[tex]'x'[/tex] represent the length of the rectangle

[tex]\frac{2x}{3}[/tex] represents the width of the rectangle

Substitute the values in the formula we get,

[tex]2( x+ \frac{2x}{3}) = 40\\\\\implies \frac{3x+2x}{3} =20\\\\\implies \frac{5x}{3} = 20\\\\\implies x = 12[/tex]

Length [tex]= 12[/tex] feet

Width [tex]= \frac{2(12)}{3}[/tex]

         [tex]= 8[/tex] feet

Hence, length and width of a given rectangle is equals to [tex]12[/tex] feet and [tex]8[/tex] feet respectively.

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