Respuesta :
Data:
m = 7 g
ΔT = 19 °C
Cs of water = 1 cal / g °C
Formula Q = m * Cs * ΔT
Solution:
Q = (7 g) * (1 cal / g °C) * ( 19°C) = 133 cal
m = 7 g
ΔT = 19 °C
Cs of water = 1 cal / g °C
Formula Q = m * Cs * ΔT
Solution:
Q = (7 g) * (1 cal / g °C) * ( 19°C) = 133 cal
Answer: The heat required is 556.738 Joules.
Explanation:
To calculate the heat required, we use the equation:
[tex]Q= m\times c\times \Delta T[/tex]
where,
Q = heat absorbed = ? Joules
m = mass of water = 7g
c = heat capacity of water = 4.186 J/g ° C
[tex]\Delta T=\text{Change in temperature}=19^oC[/tex]
Putting values in above equation, we get:
[tex]Q=7g\times 4.186J/g^oC\times 19^oC[/tex]
Q = 556.738 J
Hence, the heat required by water is 556.738 Joules.