Respuesta :

The magnitude of the ray from the origin to 1+1 is sqrt(2).

Thus, 1+i becomes sqrt(2) <pi/4 in polar form.

The complex number in polar form will be z = √2(cos 45°+isin 45°)

What is De Moivre's theorem for exponentiation of complex numbers?

Any complex number z = a + ib can be written in polar form as:

[tex]z = r(\cos(\theta) + i\sin(\theta))[/tex]

Raising this to nth power (n being an integer), we get:

[tex]z ^n = r^n (\cos(n\theta) + i\sin(n\theta))[/tex]

We know that Complex value z is written in a rectangular form as z = x+iy where (x, y) is the rectangular coordinates.

On converting the rectangluar to polar form of the complex number;

x = rcosθ and y = rsinθ

We need to Convert 1 + i to polar form,

The magnitude of the ray from the origin;

[tex]x^{2} +y^{2} = r^{2}[/tex]

[tex]r^{2}[/tex]=  1 + 1

r = √2

r is the modulus of the complex number and θ is the argument, θ = tan⁻¹y/x

θ = tan⁻¹ (1/1)

θ = tan⁻¹ (1)

θ = 45°

Hence the complex number in polar form will be z = √2(cos 45°+isin 45°)

Learn more about cube root of complex numbers here:

https://brainly.com/question/16048106

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