Respuesta :
Area=1/2*base*height
given that ABC is right angled triangle, the height will be given by:
tan theta=opposite/adjacent
tan 60=h/6
h=6tan60
=10.4
thus the area will be:
A=1/2x6x10.4
=31.2 cm^2
given that ABC is right angled triangle, the height will be given by:
tan theta=opposite/adjacent
tan 60=h/6
h=6tan60
=10.4
thus the area will be:
A=1/2x6x10.4
=31.2 cm^2
Answer:
CD = 3√3 cm
Area ΔABC =18cm²
Step-by-step explanation:
the angle < ACB =90°
<ACD =60° therefore <BCD =30°
cos 30°= x/6
x= 3√3 cm
Area ΔABC =1/2×base×height
the ΔABC is a 45 45 90 triangle
: AC =6√3 cm
ΔABC = 1/2×6√3×6
ΔABC =18√3 cm²