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For a concert,there were 206 more tickets sold at the door than were sold in advance. The tickets sold at door cost $10 and the tickets sold in advance cost $6. The total amount of sales for both types of tickets was $6828. How many of each type of ticket was sold.

Respuesta :

they were sold for a record price of breaking me... 

Let the number of tickets sold in advance be 'x'

Since, the number of tickets sold at door were 206 more than 'x'.

So, the number of tickets sold at door = 206+x

According to the question,

Amount of sale from tickets sold at the door =$ [tex] (206+x) \times 10 [/tex]

Amount of sale from advanced tickets = $ [tex] 6 \times x [/tex]

The total amount of sales for both types of tickets = $6828.

[tex] (206+x) \times 10 + 6x =6828 [/tex]

[tex] 2060+10x+ 6x =6828 [/tex]

[tex] 2060+16x =6828 [/tex]

[tex] 16x = 4768 [/tex]

[tex] x=\frac{4768}{16} [/tex]

x=298

Total number of tickets sold in advance = 298

Total number of tickets sold at the door = 206+298 = 504.

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