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A parent pulls a child in a wagon at a constant speed. If the parent pulls with a force of 16N for 12 m and the handle is inclined at 25 degrees above the horizontal how much work does the parent do on the wagon?

Respuesta :

jennyli013
W=Fd*(cos theta)
W=16N*(12m)*(cos 25)
W=174J
hamzaahmeds

This question involves the concept of work done and force.

The work done by the parent is "174 J".

WORK DONE

Work done is defined as the product of the force applied on the object and the component of distance traveled by the object in the direction of the force. Mathematically,

[tex]W=FdCos\theta[/tex]

where,

  • W = work done = ?
  • F = force applied = 16 N
  • d = displacement = 12 m
  • θ = angle of inclination = 25°

Therefore,

[tex]W=(16\ N)(12\ m)Cos(25^o)[/tex]

W = 174 J

Learn more about work done here:

https://brainly.com/question/4095205

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