One hour after a hiker left a camp, a cyclist set out to catch up. If the hiker traveled 3 miles per hour and the cyclist traveled 6 miles per hour faster, how long will it take the cyclist to catch up with the hiker?

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Respuesta :

3mph and 6mph
1 hour
30 minutes for the cyclist to catch up

Answer:

30 minutes

Step-by-step explanation:

We use the equation d = rt for this situation.

For the hiker, r = 3.  The hiker also travels for an hour more than the cyclist; this means that in place of t, we use t+1.  This gives us:

d = 3(t+1)

For the cyclist, r = 3+6 = 9.  This gives us

d = 9t

Since they travel the same distance, we set them equal:

3(t+1) = 9t

Using the distributive property,

3(t)+3(1) = 9t

3t+3 = 9t

Subtract 3t from each side:

3t+3-3t = 9t-3t

3 = 6t

Divide both sides by 6:

3/6 = 6t/6

0.5 = t

It takes the cyclist 1/2 hour, or 30 minutes, to catch up.