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How many atoms of gold of (196.97 g/mol) are in a gold nugget with a mass of 4.25g, and there are answer is 1.30⋅10^22 with molecules or atoms of gold.
How many atoms of gold of (196.97 g/mol) are in a gold nugget with a mass of 4.25g, and there are answer is 1.30⋅10^22 with molecules or atoms of gold.
Answer : The number of atoms of gold is, [tex]1.32\times 10^{22}[/tex]
Explanation : Given,
Mass of gold = 4.25 g
Molar mass of gold = 196.96 g/mole
First we have to calculate the moles of gold.
[tex]\text{Moles of gold}=\frac{\text{Mass of gold}}{\text{Molar mass of gold}}=\frac{4.25g}{196.96g/mole}=0.022mole[/tex]
Now we have to calculate the number of atoms of gold.
As, 1 mole of gold contains [tex]6.022\times 10^{23}[/tex] number of gold atoms
So, 0.022 mole of gold contains [tex]0.022\times (6.022\times 10^{23})=1.32\times 10^{22}[/tex] number of gold atoms
Therefore, the number of atoms of gold is, [tex]1.32\times 10^{22}[/tex]
