Respuesta :
Simplify the following:
(5 i^3 t^4)/7 - 2
i^3 = i^2×i = (-1) i = -i:
(5×-i t^4)/7 - 2
Put each term in (5 (-i) t^4)/7 - 2 over the common denominator 7:
(5 (-i) t^4)/7 - 2 = (-5 i t^4)/7 - 14/7:
(-5 i t^4)/7 - 14/7
(-5 i t^4)/7 - 14/7 = (-5 i t^4 - 14)/7:
Answer: (-5 i t^4 - 14)/7
(5 i^3 t^4)/7 - 2
i^3 = i^2×i = (-1) i = -i:
(5×-i t^4)/7 - 2
Put each term in (5 (-i) t^4)/7 - 2 over the common denominator 7:
(5 (-i) t^4)/7 - 2 = (-5 i t^4)/7 - 14/7:
(-5 i t^4)/7 - 14/7
(-5 i t^4)/7 - 14/7 = (-5 i t^4 - 14)/7:
Answer: (-5 i t^4 - 14)/7
i^3= -1
[tex] \frac{5i^{3}t^{4} }{7} = -\frac{5it^4}{7} [/tex]
[tex]\frac{5i^{3}t^{4} }{7} = -\frac{5it^4}{7} = answer-2- \frac{5t^4}{7}i [/tex]
[tex] \frac{5i^{3}t^{4} }{7} = -\frac{5it^4}{7} [/tex]
[tex]\frac{5i^{3}t^{4} }{7} = -\frac{5it^4}{7} = answer-2- \frac{5t^4}{7}i [/tex]