1. substitution....because it would be easier to just sub one y in for the other then it would be to use the elimination method
2. substitution....because in one of the equations, u already have y...so just sub 6x - 13 in for y in the other equation
3. elimination....all u have to do is add them and ur y terms are eliminated, allowing u to find x
4. substitution....sub in x + 1 for y in the other equation
2x + 4(x + 1) = 28 y = x + 1
2x + 4x + 4 = 28 y = 4 + 1
6x = 24 y = 5
x = 4
the solution for this system is : (4,5)
5. elimination..
3x - y = -1 3(-2) - y = -1
2x + y = -9 -6 - y = -1
------------------add -y = -1 + 6
5x = -10 -y = 5
x = -2 y = -5
the solution to this system is : (-2,-5)
6. substitution.....sub in one y for the other
2/3x - 1 = -x + 4 y = -x + 4
2/3x + x = 4 + 1 y = -3 + 4
5/3x = 5 y = 1
x = 5 * 3/5
x = 3
so the solution to this system is (3,1)
7. substitution...sub one y in for the other
296 - 10x = 200 + 6x y = 200 + 6(6)
296 - 200 = 6x + 10x y = 200 + 36
96 = 16x y = 236
6 = x
so the solution for this system is (6,236)
