Respuesta :
Answer is: selenium (Se).
1) electron configuration: ₃₄Se 1s²2s²2p⁶3s²3p⁶3d¹⁰4s²4sp⁴.
2) ₃₃As 1s²2s²2p⁶3s²3p⁶3d¹⁰4s²4sp³.
3) ₃₆Kr 1s²2s²2p⁶3s²3p⁶3d¹⁰4s²4sp⁶.
4) ₃₁Ga 1s²2s²2p⁶3s²3p⁶3d¹⁰4s²4sp¹.
Valence electrons of selenium are 4s²4sp⁴.
1) electron configuration: ₃₄Se 1s²2s²2p⁶3s²3p⁶3d¹⁰4s²4sp⁴.
2) ₃₃As 1s²2s²2p⁶3s²3p⁶3d¹⁰4s²4sp³.
3) ₃₆Kr 1s²2s²2p⁶3s²3p⁶3d¹⁰4s²4sp⁶.
4) ₃₁Ga 1s²2s²2p⁶3s²3p⁶3d¹⁰4s²4sp¹.
Valence electrons of selenium are 4s²4sp⁴.
Answer : The correct option is, (1) Se
Explanation :
Electronic configuration : It is defined as the representation of electrons around the nucleus of an atom.
Number of electrons in an atom are determined by the electronic configuration.
Atomic number : It is defined as the number of electrons or number of protons present in a neutral atom.
(1) The given atom is, selenium (Se)
Atomic number of Se = 34
Number of electrons = 34
The electronic configuration of selenium atom is,
[tex]1s^22s^22p^63s^23d^{10}4s^24p^4[/tex]
Number of valance electrons = 6
(2) The given atom is, arsenic (As)
Atomic number of As = 33
Number of electrons = 33
The electronic configuration of arsenic atom is,
[tex]1s^22s^22p^63s^23d^{10}4s^24p^3[/tex]
Number of valance electrons = 5
(3) The given atom is, krypton (Kr)
Atomic number of Kr = 36
Number of electrons = 36
The electronic configuration of krypton atom is,
[tex]1s^22s^22p^63s^23d^{10}4s^24p^6[/tex]
Number of valance electrons = 8
(4) The given atom is, gallium (Ga)
Atomic number of Ga = 31
Number of electrons = 31
The electronic configuration of gallium atom is,
[tex]1s^22s^22p^63s^23d^{10}4s^24p^1[/tex]
Number of valance electrons = 3
Hence, from this we conclude that the selenium element has six valence electrons in each of its atoms in the ground state.