Respuesta :

altavistard
Let the lesser even integer be n.

Then 3n = 6(n+2)-6
          3n = 6n + 12 - 6
           -6 + 3n, and n = -2

The greater even integer is 0.

Check:  3(-2) = 6(0)-6
               -6    =   -6   true

fichoh

The required integer is - 2

We could express the two consecutive even ntegers as :

n and n+2

Lesser integer = n

greater integer = n + 2

Three times the lesser = 3n

Six times the greater = 6(n+2)= 6n + 12

3n = (6n + 12) - 6

3n = 6n + 12 - 6

3n = 6n + 6

3n - 6n = 6

-3n = 6

n = 6/-3

n = - 2

The integer is - 2

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