The motion of the apple is a free fall motion, so it is a uniformly accelerated motion. Therefore, we can use the following equation:
[tex] v^2-u^2 =2gh [/tex]
where
v=8 m/s is the speed of the apple when it hits the ground
u=0 is the initial speed of the apple
[tex] g=9.81 m/s^2 [/tex] is the free-fall acceleration
h is the height from which the apple has fallen
Substituting data and rearranging the equation, we can find the height of the tree, h:
[tex] h=\frac{v^2}{2g}=\frac{(8 m/s)^2}{2(9.81 m/s^2)}=3.26 m [/tex]
