Answer:
The first one is y-axis, the second one is y= -x
Step-by-step explanation:
When a point is reflected it must be reflected over a line
From the complete question, the given parameters are:
[tex]\mathbf{K =(5,2)}[/tex] [tex]\mathbf{K' =(-5,2)}[/tex]
[tex]\mathbf{I =(-3,-2)}[/tex] [tex]\mathbf{I' =(-2,3)}[/tex]
(a) From K to K'
We have:
[tex]\mathbf{K =(5,2)}[/tex]
[tex]\mathbf{K' =(-5,2)}[/tex]
Notice that, only the x-coordinate of point K is negated to form point K'
This means that: the transformation from K to K' is:
[tex]\mathbf{(x,y) \to (-x,y)}[/tex]
The above transformation represents a reflection across the y-axis.
i.e.
[tex]\mathbf{(5,2) \to (-5,2)}[/tex]
Hence, the transformation from K to K' is a reflection over the y-axis
(b) From I to I'
We have:
[tex]\mathbf{I =(-3,-2)}[/tex]
[tex]\mathbf{I' =(-2,3)}[/tex]
Notice that, the x and y coordinates of I are swapped, and then the new y-coordinate is negated to form I'
This means that: the transformation from I to I' is:
[tex]\mathbf{(x,y) \to (y,-x)}[/tex]
The above transformation represents a reflection across the line y = - x
i.e.
[tex]\mathbf{(-3,-2) \to (-2,3)}[/tex]
Hence, the transformation from I to I' is a reflection over the line y= -x
Read more about reflections at:
https://brainly.com/question/17983440
