Respuesta :

Dejanras
Answer is: volume of gold  equal in mass to a piece of copper is 46,89 ml.
d(Cu) = 8,96 g/ml.
V(Cu) = 101 ml.
d(Au) = 19,3 g/mol.
V(Au) = ?.
m(Cu) = d(Cu) · V(Cu)
m(Cu) = 8,96 g/ml · 101 ml
m(Cu) = 905 g.
m(Au) = m(Cu) = 905 g.
V(Au) = m(Au) ÷ d(Au)
V(Au) = 905 g ÷ 19,3 g/ml.
V(Au) = 46,89 ml.

david8644

Answer:

We need 46,88 ml of gold to have the same mass as 101 ml of copper

Explanation:

First we have to calculate the mass of the piece of copper, remember that ml is a measure for volume, so we just have to solve the formula of density for mass:

Density=mass/volume

Mass=volume*density

And we instert the data that we knwo:

Mass=101*8.96

Mass= 904,96 grams

SO know that we now the mass of the copper piece, we can solve for volume in the formula of density to get how many mililiters of gold we need to have 904,96 grams:

Density=mass/volume

Volume=Mass/density

Volume= 904,96/19,3

Volume=46,88 mililiters

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