Respuesta :
The major trigonometric ratios at this level include sine, cosine and tangent.
sine is the ratio of opposite to hypotenuse, cosine is the ratio of adjacent to hypotenuse while tan is the ratio of opposite to adjacent. Therefore, in this case our adjacent is 15, To get the hypotenuse we use the pythagoras theorem
15² + 9² = 346, thus the hypotenuse will be √346.
Hence, cos B will be 15/√346
sine is the ratio of opposite to hypotenuse, cosine is the ratio of adjacent to hypotenuse while tan is the ratio of opposite to adjacent. Therefore, in this case our adjacent is 15, To get the hypotenuse we use the pythagoras theorem
15² + 9² = 346, thus the hypotenuse will be √346.
Hence, cos B will be 15/√346
Pythagorean theorem can be used for evaluating the one unknown side in a right angled triangle. The value of cosine B is [tex]\dfrac{15}{\sqrt {346}}[/tex].
Given the length of side a is 15 units, the length of side b is 11 units and the triangle ABC is right angled at C.
Question is asked to find the cosine value of angle B.
- The base and the perpendicular is depends on the angle that has to be taken in trigonometric function.
- The side which is present in front of the angle is always taken as the perpendicular of the triangle.
- The side which is present side by side of the angle is always consider as the base of the triangle.
- The longest side is the hypotenuse of the triangle.
Therefore, according to the questions.
Base is 15 units
Perpendicular is 11 units.
Now, apply the Pythagoras theorem, and solve it further.
[tex]H^2=15^2+11^2\\H=\sqrt{346}[/tex]
Thus,
The value of cosine B is [tex]\dfrac{15}{\sqrt {346}}[/tex].
To know more about Pythagoras, please refer to the link:
https://brainly.com/question/15138986