Suppose you have just enough money, in coins, to pay for a loaf of bread priced at $1.95. You have 12 coins, all quarters and dimes. Let q equal the number of quarters and d equal the number of dimes. Which system models the given information?

a.
q + d = 12
q + d = 1.95

c.
25q + 10d = 1.95
q + 12 = d

b.
0.10q + 0.25d = 12
q + d = 1.95
d.
q + d = 12
0.25q + 0.10d = 1.95

Respuesta :

well you have 1.95 and u have 12 coin , so u add 4 quarter is one dollar and u need 8 dime one more quarter


Answer:

Option D is correct

q + d = 12

0.25q + 0.10d = 1.95

Step-by-step explanation:

Given is , you have q quarters and d dimes totaling to 12 coins, all of which are either quarters or dimes, [tex]q+d=12[/tex] .... (1)

We know that the value of a quarter is 25 cents

So the value of all q quarters is 25q cents.

Similarly, the value of your d dimes is 10d cents.

Now given total value of your money is $1.95 = 195 cents so equation is :

[tex]25q+10d=195[/tex] or the value of the quarters can be given as .25q and the value of dimes as .10d, making equation =

[tex]0.25q+0.10d=1.95[/tex] .....(2)

Hence, these two equations are in option D. So, D is correct.