Respuesta :

When we look at the sequence, we can see that the change is *-3 each time. So we simply do that until the 9th term
7/9, -7/3, 7, -21, 63, -189, 567, -1701, 5103

Hope this helps

The variables that we have in a geometric progression are

a , which is the first term = [tex] \frac{7}{9} [/tex]

r which is the common ratio got by dividing any two consecutive terms

[tex] r= \frac{\frac{-7}{3}}{\frac{7}{9}} [/tex]

[tex] r= \frac{-7}{3} . \frac{9}{7} [/tex]

[tex] r=-3 [/tex]

n is the number of terms = 9

The n th term is given by the formula

a₉ = a.[tex] r^{n-1} [/tex]

[tex] =\frac{7}{9}. (-3)^{9-1} [/tex]

[tex] \frac{7}{9} .(-3)^{8} [/tex]

=[tex] \frac{7}{9} . 6561 [/tex]

=[tex] \frac{45927}{9} [/tex]

a₉ = 5103