Find the area of the shaded regions. Give your answer as a completely simplified exact value in terms of π (no approximations).

Answer:
the answer is 13 1/3 pi.
Step-by-step explanation:
first, you solve the area of the smaller circle, 3^2 times pi, 9pi. since 120 is 1/3 360, it means it is 1/3 of the cirlce. 9/3=3. 3 is what you have to subtract. next, you know the radius of the big circle is 7 and 7^2 times pi is 49 pi. again, you know 120 is 1/3 360 so it has to be 49/3 pi. 49/3pi - 3pi= 13 1/3 pi.
Area of the shaded regions is [tex]13\frac{1}{3}\pi[/tex] square cm.
"Area of a circle is the region occupied by the circle in a two-dimensional plane. It can be determined easily using a formula, A = [tex]\pi r^{2}[/tex], where r is the radius of the circle. The unit of area is the square unit, such as square meter, square centimeter, etc."
We have
Inner circle radius = 3cm
Outer circle radius = 4 + 3 cm = 7cm
Formula to find the area of circle
A = [tex]\pi r^{2}[/tex]
Area of inner circle
A = [tex]\pi. 3^{2}[/tex]
⇒ A = [tex]9\pi[/tex]
Since, [tex]120^{0}[/tex] is [tex]\frac{1}{3} of 360^{0}[/tex]
Thus, it means the shaded area of the figure is of [tex]\frac{1}{3}[/tex] of the circle.
∴ A = [tex]\frac{9\pi }{3}[/tex]
⇒ A = [tex]3\pi[/tex] square cm
Area of outer circle
A = [tex]\pi. 7^{2}[/tex]
⇒ A = [tex]49\pi[/tex]
Since, it means the shaded area of the figure is of [tex]\frac{1}{3}[/tex] of the circle.
∴ A = [tex]\frac{49\pi }{3}[/tex] square cm
Area of the shaded regions = Area of outer circle - Area of inner circle
A = [tex]\frac{49\pi }{3}-3\pi[/tex]
⇒ A = [tex]\frac{49\pi-9\pi }{3}[/tex]
⇒ A = [tex]\frac{40\pi }{3}[/tex]
⇒ A = [tex]13\frac{1}{3}\pi[/tex] square cm
Hence, Area of the shaded regions is [tex]13\frac{1}{3}\pi[/tex] square cm.
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