If the area of the rectangle and parallelogram is 34 and 6. Then the area of the figure will be 40 cubic units.
What is the area of rectangle and parallelogram?
The area of the figure will be
Area = area of rectangle + area of parallelogram
The length of the rectangle will be
[tex]\rm L = \sqrt{(2+6)^2+(1+1)^2}\\\\L = 8.2462[/tex]
The length of the rectangle will be
[tex]\rm B = \sqrt{(-6+5)^2+(-1+5)^2}\\\\B = 4.1231[/tex]
The area of the rectangle will be
[tex]\rm A_R = 8.2462 \times 4.1231\\\\A_R = 34[/tex]
The base of the parallelogram will be
[tex]\rm b = \sqrt{(3+3)^2+(3-3)^2}\\\\b= 3[/tex]
The height of the parallelogram will be
[tex]\rm h= \sqrt{(3-2)^2}\\\\h= 1[/tex]
The area of the parallelogram will be
[tex]\rm A_P = 6 \times 1\\\\A_P = 6[/tex]
Then the area of the figure will be
Area = 6 + 34
Area = 40
More about the area of rectangle and parallelogram link is given below.
https://brainly.com/question/16204735
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