An aerobatic airplane pilot experiences weightlessness as she passes over the top of a loop-the-loop maneuver. the acceleration of gravity is 9.8 m/s 2 . if her speed is 210 m/s at this time, find the radius of the loop. answer in units of km.

Respuesta :

 For "weightlessness," gravity = centripetal acceleration 
 g = v² / r 
 r = v² / g = (210m/s)² / 9.8m/s² = 4500 m = 4.5 km 
 The answer is 4.5 Km (
radius of the loop)

For weightless object, the gravity is equal to the centripetal acceleration.   The radius of the loop is 4.5 km.

Centripetal Acceleration formula is,

[tex]\rm \bold { a = \frac{V^2}{r} }[/tex]

Where,

V-  velocity =  210 m/s

r -  radius = ?

As we know that for weightless object,

Gravity =  centripetal acceleration

hence a =  g

g = [tex]\rm \bold{ 9.8 m/s ^2}[/tex]

put the value in the formula,

[tex]\rm \bold { 9.8 = \frac{ 210 ^2}{r} }[/tex]

[tex]\rm \bold {r = \frac{ (210 m/s)^2}{ 9.8m/s^2 } }\\\\\rm \bold {r = 4500m}\\\\\rm \bold {r = 4.5 km }[/tex]

Hence, we can conclude that the radius of the loop is 4.5 km.

To know more about centripetal acceleration, refer to the link:

https://brainly.com/question/14465119